Simple Speed of Light Calculation Problem Help (I will have your baby)? - spaceship birthday cake
2. Time Travel Light
The friendly alien creature Yoda lives in a spaceship away from 1.59 × 1014 km, the stars Altair rightnear. On his 21st Birthday XxxGdl4a radiates a special anniversary messageto you with the speed of light. How old is the birthday message when it reaches the earth?
Thursday, January 7, 2010
Spaceship Birthday Cake Simple Speed Of Light Calculation Problem Help (I Will Have Your Baby)?
Subscribe to:
Post Comments (Atom)
3 comments:
Then you should know that the light with 3 x 10 ^ 8 meters per second, it will be 1.59 x 10 ^ 17 meters
Moreover, it is 530000000 seconds
530,00,000 / 60 / 60 / 24 = 6,134.26 day, of which 16 years 290 days 6 hours
16 years 9 months 17 days and 6 hours later, he was 37 years 9 months 17 days
Speed of light 3 x 10 ^ 8 meters per second.
If you live to 1.59 x 10 ^ 14 km, or 1.59 x 10 ^ 17 m.
Speed = distance / time so time = distance / speed
1.59 x 10 ^ 17 / 3 x 10 ^ 8 = 5.3 x 10 ^ 8 seconds
Dividing by the number of seconds in 1 year, is 31,536,000 and you get 16.8 years.
It would be 37 years old when he received the message) (4 months after his 38th birthday.
37 years 9 months 22 days (or, what comes to 38). Speed of light, m (c) = 3 * 10 ^ 8 / s. It is the simple answer.
However, there is a problem with the acceptance of your request "on his 21st birthday. Simultaneity at a distance is not applicable, so that aspect really makes no sense: see http://en. Org / wiki / Relativity_of_simultaneity
Post a Comment